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Delta G for the reaction (4)/(3) Al + O(...

`Delta G` for the reaction `(4)/(3) Al + O_(2) rarr (2)/(3) Al_(2)O_(3)` is `-772kJ mol^(-1)` of `O_(2)`. Calculate the minimum EMF in volts required to carry out an electrolysis of `Al_(2)O_(3)`

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The correct Answer is:
2
`Al rarr Al^(3+)+ 3e^(-)`
`(4)/(3)` mol of `Al = (4)/(3) xx 3` mole `e^(-e)= 4 mol e^(-)`
`n=4 Delta- nFE`
`-772 xx 1000J = -4 xx 96500 xx E therefore E= (772 xx 1000)/(4 xx 96500)= 2.0V`
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