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k = 4.95 xx 10^(-5) S cm^(-1) for a 0.00...

`k = 4.95 xx 10^(-5) S cm^(-1)` for a 0.001M solution. The reciprocal of the degree of dissociation of acetic acid, if `Lamda_(m)^(@)` for acetic acid is `400 S cm^(-2) mol^(-1)` is

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The correct Answer is:
8
`k=4.95 xx 10^(-)S cm^(-1 ) , alpah = (Lamda_(m))/(Lamda_(m)^(@))rtf54`
`Lamda_(m) = 1000 xx (k)/( C) = 1000 xx (4.95 xx 10^(-5))/(0.001)= 49.5 S cm^(-1) rArr alpha = (49.5)/(400) rArr (1)/(alpha) = (400)/(49.5) ~~ 8`
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