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During the first 18 min of a 60 min trip...

During the first 18 min of a 60 min trip, a car has an average speed of `11ms^(-1)`. What should be the average speed for remaining 42min so that car is having an average speed of `21 ms^(-1)` for the entire trip?

A

`25.3ms^(-1)`

B

`29.2ms^(-1)`

C

`31ms^(-1)`

D

`35.6ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`V_(av)=d/t =(d_1+d_2)/(t_1+t_2), 21 = ((18)(11)+(42)(V))/60 implies v=25.3 m//s`
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