A ball is released from the top of a tower of heighth metre. It takes T second to reach the ground. What is the position of the ball in T/3 second?

Options

A. `h/9` metre from the ground
B. (7h/9) metre from the ground
C. (8h/9), metre from the ground
D. (17h/18) metre from the ground

Answer

C

Explanation

`h=1/2 gT^2`
`At T/3 " second , distance fallen d=1/2 g(T/3)^2=h/9`
`:. " Height from ground " = h-d=(8h)/9`