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A drunkard walking on a narrow lane take...

A drunkard walking on a narrow lane takes 8 steps forward and 6 steps backward and so on. Each step is Im long and he requires Is to travel. The time that the drunkard takes to fall irrapit 18m away from the starting point is

A

18s

B

126s

C

78s

D

62s

Text Solution

Verified by Experts

The correct Answer is:
C

Displacement `s=8-6=2m`
For `2m, t=8+6=14s`
or time `1m =7s " for " 10m, "time " =70s`
In the next 8s , he covers 8 steps and falls into the pit.
Total time `=70+8=78s`
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