A motor car is going due east with a speed of `50 ms^(-1)`. It makes a `90^@` right tum without changing its speed The process takes 10s. The average acceleration of the motor car during this interval.

Options

A. `5sqrt2ms^(-2)`,NW
B. `5sqrt2ms^(-2)`,NE
C. `5sqrt2ms^(-2)`,SW
D. `5sqrt2ms^(-2)`,SE

Answer

C

Explanation

`vecv-vecu`
`abs(vecv-vecu)=sqrt(50^2+50^2)=50sqrt2ms^(-1), t=10s`
`:. Abs(veca_(av))=(abs(vecv-vecu))/t = (50sqrt2)/10 = 5sqrt2ms^(-2)`
The direction of `veca_(av)` is same as direction of `vecv-vecu` ie, SW`