A body of mass 2 kg has an initial velocity of 3 m/s along OE and it is subjected to a force of 4N in a directi perpendicular to OE. The distance of the body from O after 4 sec will be:

Options

A. 12m
B. 28m
C. 20m
D. 48m

Answer

C

Explanation

Along `OE : x=ut=3xx4=12 m//s`
`bot " to " OE : a_y = F/m =4/2 =2m//s^2`
`:. Y=u_y t+1/2a_yt^2`
`=(0)4+1/2(2)(4)^2=16`
`:. " Distance " =sqrt((12)^2+(16)^2) = sqrt(144+256)=sqrt400=20m`