A ball is released from the top of heighth metre. It takes T second to reach the ground. Where is the ball at the time `T/2 sec`?

Options

A. `At (h/4)m` from the ground
B. `At (h/4)m` from the ground
C. `At ((3h)/4)m` from the ground
D. Depends upon the mass and volume of the ball

Answer

C

Explanation

`h=1/2"gt"^2, " " h_1 =1/2 g(T/2)^2, " " h/h_1 = 2^2`
`h=4h_1 , " " h_1 = h/4 , " " h-h/4 =(3h)/4`