A block of mass M is pulled along a horizontal smooth surface by a rope of mass m. Force P is applied at extremity of the rope. The force exerted by the rope on the block is

Options

A. P(M+m)
B. P(M-m)
C. `(PM)/(M+m)`
D. `(PM)/(M-m)`

Answer

C

Explanation

Acceleration of block = `("Force")/("Total mass") therefore` a = `P/(M+m)`
`therefore` Force on block=(Mass of block) `xx`(Acceleration) = `PM/(M+m)`