A 5 kg stationary bomb is exploded in three parts having masses in the ratio 1 : 1: 3. Parts having same mass move in perpendicuiar directions with velocity 39 m/s, then the velocity of bigger part will be

Options

A. `(10sqrt2)/3`m/s
B. `(10)/sqrt2`m/s
C. `13sqrt2`m/s
D. `15sqrt2m//s`

Answer

C

Explanation

Momentum is conserved in the event of explosion `therefore` `p^(2/3) = p^(2/1) + p^(2/2)`
Let the masses of the three parts be m, m and 3m.
`(3mv_3)^2 = (m xx39)^2 rArr 39sqrt2 = 3v_3, v_3 = 13sqrt2 m//s`