A bomb of mass 1 kg is thrown vertically upwards with a speed of 100 `ms^(-1)` After 5 seconds, it explodes into two fragments. One fragment of mass 400 grams is found to go down with a speed of 25 `ms^(-1)` . What will happen to the second fragment must after the explosion? (Take g = 10 `ms^(-2)` )

Options

A. it will go upward with speed 100 `ms^(-1)`
B. it will go upwards with speed 40 `ms^(-r)`
C. it will go upward with speed 60` ms^(-1)`
D. it will go downwards with speed 40 `ms^(-1)`

Answer

A

Explanation

v = u - gt = 50 `ms^(-1)` , This is the velocity at the time of explosion.
According to the principle of conservation of linear momentum,
`1xx50=(400)/(1000)xx(-25)+(600)/(1000)xxv rArr v= 100 ms^(-1)`