A mass of 10 kg is suspended by a rope of length 2 m from a ceiling. A force of 75 N is applied in horizontal direction at the mid-point of the rope. The angle made by the rope, with the vertical, in equilibri position will be (Take g = 10 `ms^(-2)`, neglect the mass of the rope)

Options

A. `47^(@)`
B. `38.5^(@)`
C. `45^(@)`
D. `37^(@)`

Answer

D

Explanation

`(75)/(SA)=(10xx10)(SB)rArr(SA)/(SB)=3/4` or `tan theta=(SA)/(SB)=3/4=tan 37^@ therefore theta=37^@`