A large free mass M and a small mass m are connected to a string such that m moves in horizontal circle Length of string is I and `theta` is the angle this length makes with vertical. The frequency of rotation of mass m that M remains at rest is

Options

A. `2pisqrt((ml)/(Mg))`
B. `1/(2pi)sqrt((mg)/(Ml))`
C. `1/(2pi)sqrt((ml)/(Mg))`
D. `1/(2pi)sqrt((mg)/(ml))`

Answer

D

Explanation

`T=Mg and Tcos theta = mg
also Tsin theta=m omega^2lsin theta(thereforeradius=lsintheta)
rArrT = momega^2l , Mg= momega^2l rArromega = =2piv = 1/(2pi)sqrt(Mg)/(ml)`.