A body of 10 kg is kept prissing normally on an inclined plane of inclination `30^(@)` by a force of 200 N. T coefficent of static friction between the plane and the body is 0.3. Then the friction force is equal to

Options

A. 100 N
B. 50 N
C. 200 N
D. 300 N

Answer

B

Explanation

`F= mg sin theta = 10 xx 10 xx 1/2 = 50 N`