An aircraft executes a horizontal loop of radius 1 km with a speed of 900 km/h .Conpare its centripetal acceleration with the acceleration due to gravity .

Options

A. 6
B. 7
C. 8
D. 5

Answer

A

Explanation

Radius of horizontal loop (r ) = 1 km = 1000 m
Speed of aircraft (v ) = 900 km/h = `900 xx 5/18 m//s = 250 m//s`
Centripetal acceleration of the aircraft = `a= (v^(2))/r = ((250)^(2))/(1000)= 62500/1000 =62.5 m//s^(2)`
Acceleration due to gravity (g) = `10 m//s^(2) :. ("Centripetal acceleration (a)")/("Acceleration due to gravity (g)") =(625)/10 = 6.25 approx 6`