The force required to stretch a steel wireof 1 cm cross-section to 1.1 times its length would be
`(Y = 2xx 10^(11) Nm^(-2))`

Options

A. `2xx 10^(6) N`
B. `2 xx 10^(3)` N
C. `2 xx 10^(-6) N`
D. `2 xx 10^(-7) ` N

Answer

A

Explanation

`L_(2)= 1.1 L_(1) " " :. "Strain" = (l)/(L_(1)) = (L_(2)-L_(1))/(L_(1))= (1.1 L_(1)-L_(1))/(L_(1)) =0.1`
`F = YA (l)/(L) = 2xx 10^(11) xx 1 xx 10^(-4) xx 0.1 = 2xx 10^(6)` N