Passage II In fig., i(1)=10e^(-2t)A,i...

Passage II
In fig., `i_(1)=10e^(-2t)A,i_(2)=4A`, and `V_(C)=3e^(-2t)V`.

The variation of current in the inductor with time can ve represented as

A

B

C

D

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The correct Answer is:

A

`i_(L)` increases from 2A to 4 A exponentially.

Passage II In fig., i(1)=10e^(-2t)A,i(2)=4A, and V(C)=3e^(-2t)V. ...
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In the Figure shown i1=10e^(-2t) A, i2=4A and VC=3e^(-2t)V . Determine...
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In Fig i(1) = 10e^(-2t) A , i(2) = 4 A , and V(C) = 3e^(-2t) V . The v...
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In Fig i(1) = 10e^(-2t) A , i(2) = 4 A , and V(C) = 3e^(-2t) V . the v...
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In Fig i(1) = 10e^(-2t) A , i(2) = 4 A , and V(C) = 3e^(-2t) V . The v...
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In figure i(1) = 10 e^(-2t) A, i(2) = 4 A, v(C ) = 3 e^(-2t) V The cur...
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In figure i(1) = 10 e^(-2t) A, i(2) = 4 A, v(C ) = 3 e^(-2t) V Th...
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In figure i(1) = 10 e^(-2t) A, i(2) = 4 A, v(C ) = 3 e^(-2t) V The pot...
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In figure i(1) = 10 e^(-2t) A, i(2) = 4 A, v(C ) = 3 e^(-2t) V Th...
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