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16 g oxygen gas expands at STP to occupy...

16 g oxygen gas expands at STP to occupy double of its original volume. The magnitude of work done during the process is:

A

260 cal

B

180 cal

C

130 cal

D

271.6 cal

Text Solution

Verified by Experts

The correct Answer is:
D
At STP, 16 g `O_(2)` or `1/2` mol of `O_2` will occupy 11. 2 L volume.
Thus, if the volume is doubled, it means, `(V_2 – V_1) = 22 .4 -11 .2= 11 .2 L`
Now, `W = P xx (V_2 - V_1) = 1 xx 11 .2` litre atom = `11.2 xx 24.22 = 271.6` cal
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