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To coagulate 100 ml of a colloid, 1 litr...

To coagulate 100 ml of a colloid, 1 litre of `0.03N` `MgCl_2` is required. Then, The flocculation value of `MgCl_2` is

A

`150.`

B

`300.`

C

`100.`

D

`600.`

Text Solution

Verified by Experts

The correct Answer is:
A

Flocculation value is defined as the minimum concentration (in millimoles per litre) of an electrolyte required to cause the caogulation power of an electrolyte is usually expressed in thems of its flocculation value.
Gram equivalents of `MgCl_2`
`="Normality" xx "volume"`
`=0.03 xx 1=0,03`
`"Normality"= "molarity" xx "n.factor"`
`"molarity"="Normality"/"n.factor"=0.03/2=0.015`
100 mL of colloid requires 15 millimoles then one liter (1000 ml) requires
`(15 xx 1000)/100=150` millimoles.
So, flocculation value=150
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