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The weight of 350 mL of a diatomic gas a...

The weight of 350 mL of a diatomic gas at `0^@`C and 2 atm pressure is 1g. The weight of one atom is
(N is the Avogadro's Number)

A

`16//N`

B

32/N

C

16 N

D

32 N

Text Solution

Verified by Experts

The correct Answer is:
A
`PV = m/M RT`
`therefore 2 xx (0.35) = 1/M xx 0.0821 xx 273`
M = 32
`therefore` Atomic masss = 16
`therefore` Mass of 1 atom `= 16/N`
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