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For 1 mol of an ideal gas, V(1) gt V(2) ...

For 1 mol of an ideal gas, `V_(1) gt V_(2) gt V_(3)` in fig. 1, `T_(1) gt T_(2) gt T_(3)` in fig. 2, `P_(1) gt P_(2) gt P_(3)` in fig. 3, and `T_(1) gt T_(2) gt T_(3)` in fig. 4, then which curves are correct.

A

1,2

B

1,2,3

C

2,4

D

1,3,4

Text Solution

Verified by Experts

The correct Answer is:
C
PV = RT
If `P_(1) gt P_(2), V_(1) lt V_(2)`
Also `log P = - log V + log RT`
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