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Molecular weight of oxalic acid is 126. ...

Molecular weight of oxalic acid is 126. The weight of oxalic acid required to neutralise 100 cc of 1 normal solution of NaOH is

A

6.3 gm

B

126 gm

C

530 gm

D

63 mg

Text Solution

Verified by Experts

The correct Answer is:
A
no. of equivalent of acid = no of equivalent of Base
`(("Weight")/("Molecular weight")xx.n."factor")_("Base")=(NxxV_("liter"))_("Acid")`
`:.` n factor of NaOH=1
`:.` n factor of Oxalic acid =1
`1=(x xx1000)/(63xx100)x=6.3` gms
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Knowledge Check

  • Molecular weight of oxalic acid is 126. the weight of oxalic acid required to neutralise 100cc of normal solution of NaOH is

    A
    6.3 gm
    B
    126 gm
    C
    530 gm
    D
    63 gm

  • Molecular weight of oxalic acid is 126 weight of oxalic acid required to neutral 100 mL of normal solution of NaOH is

    A
    530 g
    B
    63 g
    C
    69 g
    D
    126 g

  • The weight of oxalic acid required to reduce 80 ml of 0.4 M KMnO_(4) in acidic medium is

    A
    10.08 g
    B
    7.21 g
    C
    16.28 g
    D
    12.4 g

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    The weight of oxalic acid dihydrate is 126. Its equivalent weight is

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    The weight of hydrated oxalic acid required to reduce 80 ml of 0.4M KMnO_(4) in acidic medium is

    20 ml of 1 N solution of KMnO_(4) just reacts with 20 ml of a solution of oxalic acid. The weight of oxalic acid crystals in 1N of the solution is

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