Molecular weight of oxalic acid is 126. The weight of oxalic acid required to neutralise 100 cc of 1 normal solution of NaOH is

Options

A. 6.3 gm
B. 126 gm
C. 530 gm
D. 63 mg

Answer

A

Explanation

no. of equivalent of acid = no of equivalent of Base
`(("Weight")/("Molecular weight")xx.n."factor")_("Base")=(NxxV_("liter"))_("Acid")`
`:.` n factor of NaOH=1
`:.` n factor of Oxalic acid =1
`1=(x xx1000)/(63xx100)x=6.3` gms