Reaction `2Br^(-)(aq)+Cl_(2)(aq)to2Cl^(-)(aq)+Br_(2)(aq)` is used for commercial preparation of bromine from its salts. Suppose we have 50 mL of a 0.60 M solution of NaBr. What volume of a 0.050 M solution of `Cl_(2)` is needed to react completely with the Br?

Options

A. V=500 mL
B. V = 400 mL
C. V = 200 mL
D. V=300 mL

Answer

D

Explanation

`2Br^(-)+Cl_(2)to2Cl^(-)+Br_(2)or2Br^(-)toBr_(2)^(0)+2e` (Valence factor for `Br^(-)=1` )
`Cl_(2)^(0)+2e^(2)to2Cl^(-)` (Valence factor for `Cl_(2)=2` )
Meq. of `Cl_(2)` =Meq. of `Br^(-)`
`0.05xx2V=50xx0.6xx1`
V=300 mL.