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In a DeltaABC, the bisectors of angleB a...

In a `DeltaABC`, the bisectors of `angleB and angleC` meet at point O within the triangle. If `angleA = 132^(@)` then the measure of `angleBOC` is(in degrees) :

A

`166^(@)`

B

`84^(@)`

C

`156^(@)`

D

`120^(@)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the measure of angle BOC in triangle ABC, given that angle A = 132 degrees. We will use the property of the incenter of a triangle, which is where the angle bisectors of the triangle meet. ### Step-by-Step Solution: 1. **Identify the Given Information**: - We have triangle ABC. - Angle A = 132 degrees. - O is the point where the angle bisectors of angles B and C meet. 2. **Understand the Incenter Property**: - The point O is the incenter of triangle ABC. - The angle BOC can be calculated using the formula: \[ \text{Angle BOC} = 90^\circ + \frac{\text{Angle A}}{2} \] 3. **Substitute the Value of Angle A**: - We know angle A = 132 degrees. - Substitute this value into the formula: \[ \text{Angle BOC} = 90^\circ + \frac{132^\circ}{2} \] 4. **Calculate the Half of Angle A**: - Calculate \(\frac{132^\circ}{2}\): \[ \frac{132^\circ}{2} = 66^\circ \] 5. **Add 90 degrees to Half of Angle A**: - Now, add 90 degrees to 66 degrees: \[ \text{Angle BOC} = 90^\circ + 66^\circ = 156^\circ \] 6. **Final Answer**: - Therefore, the measure of angle BOC is: \[ \text{Angle BOC} = 156^\circ \] ### Conclusion: The measure of angle BOC is 156 degrees.
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