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DeltaXYZ is right angled at Y. If sinX=4...

`DeltaXYZ` is right angled at Y. If `sinX=4//5`, then what is the value of `cosZ` ?

A

`3//4`

B

`5//3`

C

`4//5`

D

`4//3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( \cos Z \) given that \( \sin X = \frac{4}{5} \) in the right-angled triangle \( \Delta XYZ \) which is right-angled at \( Y \). ### Step-by-step Solution: 1. **Understanding the Triangle**: - We have a right-angled triangle \( \Delta XYZ \) with the right angle at \( Y \). - The angles are \( X \), \( Y \), and \( Z \). 2. **Using the Sine Function**: - We know that \( \sin X = \frac{\text{Opposite}}{\text{Hypotenuse}} \). - Here, the side opposite to angle \( X \) is \( YZ \) and the hypotenuse is \( XZ \). - Therefore, we can write: \[ \sin X = \frac{YZ}{XZ} = \frac{4}{5} \] - This implies that \( YZ = 4k \) and \( XZ = 5k \) for some positive constant \( k \). 3. **Finding the Third Side**: - To find the length of \( YX \), we can use the Pythagorean theorem: \[ XZ^2 = YZ^2 + YX^2 \] - Substituting the known values: \[ (5k)^2 = (4k)^2 + YX^2 \] \[ 25k^2 = 16k^2 + YX^2 \] \[ YX^2 = 25k^2 - 16k^2 = 9k^2 \] \[ YX = 3k \] 4. **Finding \( \cos Z \)**: - Now, we can find \( \cos Z \). The cosine function is defined as: \[ \cos Z = \frac{\text{Adjacent}}{\text{Hypotenuse}} \] - In the context of angle \( Z \): - The side adjacent to angle \( Z \) is \( YX \) and the hypotenuse is \( XZ \). - Therefore: \[ \cos Z = \frac{YX}{XZ} = \frac{3k}{5k} = \frac{3}{5} \] 5. **Final Answer**: - Thus, the value of \( \cos Z \) is: \[ \cos Z = \frac{3}{5} \]
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