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The average of nine 2 digit numbers is d...

The average of nine 2 digit numbers is decreased by 6 when the digits of one of the 2 digit numbers is interchanged. Find the difference between the digits of that number.

A

6

B

8

C

2

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow this approach: ### Step 1: Define the two-digit number Let the two-digit number be represented as \(10x + y\), where \(x\) is the tens digit and \(y\) is the units digit. ### Step 2: Set up the average equation The average of nine two-digit numbers is given by: \[ \text{Average} = \frac{\text{Sum of 9 numbers}}{9} \] If we denote the sum of the other eight two-digit numbers as \(S\), the average can be expressed as: \[ \text{Average} = \frac{S + (10x + y)}{9} \] ### Step 3: Interchanging the digits When the digits of the number are interchanged, the new number becomes \(10y + x\). The new average after interchanging the digits will be: \[ \text{New Average} = \frac{S + (10y + x)}{9} \] ### Step 4: Set up the equation based on the problem statement According to the problem, the average decreases by 6 when the digits are interchanged. Thus, we have: \[ \frac{S + (10x + y)}{9} - 6 = \frac{S + (10y + x)}{9} \] ### Step 5: Eliminate the fractions To eliminate the fractions, multiply the entire equation by 9: \[ S + (10x + y) - 54 = S + (10y + x) \] ### Step 6: Simplify the equation Now, we can simplify the equation: \[ 10x + y - 54 = 10y + x \] Rearranging gives: \[ 10x - x + y - 10y = 54 \] This simplifies to: \[ 9x - 9y = 54 \] ### Step 7: Solve for the difference between the digits Dividing the entire equation by 9: \[ x - y = 6 \] Thus, the difference between the digits \(x\) and \(y\) is 6. ### Final Answer The difference between the digits of the number is **6**. ---
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