A man borrows Rs. 21000 at 10% compound interest. How much he has to pay equally at the end of each year, to settle his loan in two years?

Options

A. Rs 12000
B. Rs 12100
C. Rs 12200
D. Rs 12300

Answer

B

Explanation

माना कि प्रत्येक किस्त की राशि Rs x है
`:. 21000=(x)/((1+(10)/(100)))+(x)/((1+(10)/(1000))^(2))`
`rArr 21000=(x xx10)/(11)+(100x)/(121)`
`rArr2100xx121=110x+100x`
`rArr x=(21000)/(210)xx121`
`rArr x=Rs 12100`