The price of an article was in creased by r%. Later the new price was decreased by r%.. If the latest price was 1, then the original price was:

Options

A. 1
B. Rs.`((1-r^(2) )/(100))`
C. Rs. `((sqrt(1-r^(2)))/(100))`
D. Rs. `((10000)/(10000-r^(2)))`

Answer

D

Explanation

मन की वस्तु की मूल्य `= Rs . x`
`r%` वृद्धि होने पर `to ( x xx ( 100 + r) )/( 100)`
फिर `r%` कमी होने पर `to ( x ( 100 + r) )/( 100) xx ( ( 100 - r) )/( 100)`
प्रश्न से,
`( x { ( 100)^2 - ( r)^2} )/( 10000 ) = 1`
`therefore x = (10000)/( 10000 - r^2)`