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A number is increased by 20% and again i...

A number is increased by 20% and again increase by 20%. Then the increased number should be decreased by how much percent so that the later number equals initial numbers?

A

`30(5)/(9)%`

B

`19(11)/(31)%`

C

`40%`

D

`44%`

Text Solution

Verified by Experts

The correct Answer is:
A
दो बर `20%` की वृद्धि होने पर अभीष्ट `%` वृद्धि
`= ( 20 + 20 + ( 20 xx 20 )/( 100) ) % = 44%`
अब वांछित % कमी `={ ( 44 xx 100)/( ( 100 + 44) ) } % = ( 4400)/( 144) %`
`= ( 275)/( 9 ) % = 30 ( 5)/(9) %`
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