A boy gives 80% of his pocket money to his friend and 6% of remaining to another friend. He has now 47 paise remaining. How much money did the boy has initially?

Options

A. Rs. `2`
B. Rs. `2.50`
C. Rs. `5`
D. Rs. `10`

Explanation

To find out how much money the boy had initially, we can follow these steps:

### Step 1: Define the initial amount
Let the initial amount of pocket money the boy had be \( x \) (in rupees).

### Step 2: Calculate the amount given to the first friend
The boy gives away 80% of his pocket money to his first friend. Therefore, the amount given to the first friend is:
\[ \text{Amount given to first friend} = 0.80x \]

### Step 3: Calculate the remaining amount after the first friend
After giving away 80% of his pocket money, the remaining amount is:
\[ \text{Remaining amount} = x - 0.80x = 0.20x \]

### Step 4: Calculate the amount given to the second friend
The boy then gives 6% of the remaining amount to his second friend. The amount given to the second friend is:
\[ \text{Amount given to second friend} = 0.06 \times (0.20x) = 0.012x \]

### Step 5: Calculate the remaining amount after the second friend
After giving to the second friend, the remaining amount is:
\[ \text{Remaining amount} = 0.20x - 0.012x = 0.188x \]

### Step 6: Set up the equation based on the remaining amount
According to the problem, the boy has 47 paise remaining, which is equal to \( 0.47 \) rupees. Therefore, we can set up the equation:
\[ 0.188x = 0.47 \]

### Step 7: Solve for \( x \)
To find \( x \), we divide both sides of the equation by \( 0.188 \):
\[ x = \frac{0.47}{0.188} \]

Calculating this gives:
\[ x \approx 2.5 \text{ rupees} \]

### Conclusion
Thus, the boy had initially \( 2.5 \) rupees.

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