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Find the HCF of 2616 and 2289....

Find the HCF of 2616 and 2289.

A

109

B

328

C

327

D

108

Text Solution

AI Generated Solution

The correct Answer is:
To find the HCF (Highest Common Factor) of 2616 and 2289, we will use the prime factorization method. Here’s a step-by-step solution: ### Step 1: Prime Factorization of 2616 To find the prime factors of 2616, we can start dividing by the smallest prime numbers. - 2616 is even, so we divide by 2: \[ 2616 \div 2 = 1308 \] - 1308 is also even, divide by 2 again: \[ 1308 \div 2 = 654 \] - 654 is even, divide by 2 again: \[ 654 \div 2 = 327 \] - Now, 327 is not even, so we check for the next prime number, which is 3: \[ 327 \div 3 = 109 \] - 109 is a prime number. Thus, the prime factorization of 2616 is: \[ 2616 = 2^3 \times 3^1 \times 109^1 \] ### Step 2: Prime Factorization of 2289 Now, we will find the prime factors of 2289. - 2289 is odd, so we start with 3: \[ 2289 \div 3 = 763 \] - Next, we check if 763 is divisible by 3, 5, or 7. It is not divisible by these, but it is divisible by 109: \[ 763 \div 109 = 7 \] - 7 is a prime number. Thus, the prime factorization of 2289 is: \[ 2289 = 3^1 \times 7^1 \times 109^1 \] ### Step 3: Identify Common Prime Factors Now, we will identify the common prime factors between 2616 and 2289. - From the factorization: - 2616: \(2^3, 3^1, 109^1\) - 2289: \(3^1, 7^1, 109^1\) The common prime factors are: - \(3^1\) - \(109^1\) ### Step 4: Calculate the HCF To find the HCF, we multiply the common prime factors: \[ HCF = 3^1 \times 109^1 = 3 \times 109 = 327 \] ### Conclusion The HCF of 2616 and 2289 is **327**. ---
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