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The two roots of a quadratic equation ar...

The two roots of a quadratic equation are given as `x =(1)/(7)` and `x = (-1)/(8)` The equation can be written as:

A

(7x-1)(8x - 1) = 0

B

(7x-1)(8x + 1) = 0

C

(7x + 1)(8x - 1) = 0

D

(7x + 1)(8x + 1) = 0

Text Solution

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To derive the quadratic equation from the given roots \( x = \frac{1}{7} \) and \( x = -\frac{1}{8} \), we can follow these steps: ### Step 1: Identify the roots The roots of the quadratic equation are given as: - \( r_1 = \frac{1}{7} \) - \( r_2 = -\frac{1}{8} \) ### Step 2: Calculate the sum of the roots The sum of the roots \( S \) can be calculated using the formula: \[ S = r_1 + r_2 = \frac{1}{7} + \left(-\frac{1}{8}\right) \] To add these fractions, we need a common denominator, which is 56: \[ S = \frac{8}{56} - \frac{7}{56} = \frac{1}{56} \] ### Step 3: Calculate the product of the roots The product of the roots \( P \) is given by: \[ P = r_1 \times r_2 = \frac{1}{7} \times -\frac{1}{8} = -\frac{1}{56} \] ### Step 4: Write the quadratic equation Using the standard form of a quadratic equation based on the roots: \[ x^2 - Sx + P = 0 \] Substituting the values of \( S \) and \( P \): \[ x^2 - \frac{1}{56}x - \frac{1}{56} = 0 \] ### Step 5: Eliminate the fractions To eliminate the fractions, multiply the entire equation by 56: \[ 56x^2 - x - 1 = 0 \] ### Step 6: Factor the quadratic equation Now, we can factor the quadratic equation: \[ 56x^2 - 8x + 7x - 1 = 0 \] Grouping the terms: \[ (56x^2 - 8x) + (7x - 1) = 0 \] Factoring out common terms: \[ 8x(7x - 1) + 1(7x - 1) = 0 \] This gives us: \[ (7x - 1)(8x + 1) = 0 \] ### Final Result The quadratic equation can be written in factorized form as: \[ (7x - 1)(8x + 1) = 0 \]
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