Suppose we reoresent the distance above the ground by a positive integer and that below the ground by a negative integer, then answer the following :
An elevator descends into a mine shaft at the rate of 5 metre per minute. What will be its be its position after one hour ?

Options

A. 340 m
B. 300 m
C. `-300` m
D. `-340` m

Answer

To solve the problem, we need to calculate the total distance the elevator descends into the mine shaft after one hour.

### Step-by-Step Solution:

1. **Identify the rate of descent**: The elevator descends at a rate of 5 meters per minute.

2. **Determine the duration of descent**: The duration we are considering is 1 hour. We need to convert this into minutes since the rate is given in meters per minute.
\[ 1 \text{ hour} = 60 \text{ minutes} \]

3. **Calculate the total distance descended**: To find the total distance the elevator descends in 1 hour, we multiply the rate of descent by the total time in minutes.
\[ \text{Total distance} = \text{Rate of descent} \times \text{Time} \]
\[ \text{Total distance} = 5 \text{ meters/minute} \times 60 \text{ minutes} = 300 \text{ meters} \]

4. **Determine the position of the elevator**: Since the elevator is descending below ground level, we represent this distance as a negative integer.
\[ \text{Position after 1 hour} = -300 \text{ meters} \]

### Final Answer:
The position of the elevator after one hour will be -300 meters.

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