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The tenth tern of an A.P. sqrt(2),3sqrt(...

The tenth tern of an A.P. `sqrt(2),3sqrt(2),5sqrt(2),7sqrt(2)` . . . . . Is :

A

`11sqrt(2)`

B

12

C

`10sqrt(2)`

D

`19sqrt(2)`

Text Solution

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The correct Answer is:
To find the 10th term of the arithmetic progression (A.P.) given as \( \sqrt{2}, 3\sqrt{2}, 5\sqrt{2}, 7\sqrt{2}, \ldots \), we can follow these steps: ### Step 1: Identify the first term and common difference The first term \( a \) of the A.P. is: \[ a = \sqrt{2} \] Next, we need to find the common difference \( d \). The common difference can be calculated by subtracting the first term from the second term: \[ d = 3\sqrt{2} - \sqrt{2} = 2\sqrt{2} \] ### Step 2: Use the formula for the nth term of an A.P. The formula for the nth term \( A_n \) of an A.P. is given by: \[ A_n = a + (n - 1) \cdot d \] ### Step 3: Substitute the values into the formula We want to find the 10th term, so we set \( n = 10 \): \[ A_{10} = \sqrt{2} + (10 - 1) \cdot (2\sqrt{2}) \] ### Step 4: Simplify the expression Now we can simplify the expression: \[ A_{10} = \sqrt{2} + 9 \cdot (2\sqrt{2}) \] \[ A_{10} = \sqrt{2} + 18\sqrt{2} \] \[ A_{10} = 19\sqrt{2} \] ### Final Answer Thus, the 10th term of the A.P. is: \[ \boxed{19\sqrt{2}} \] ---
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