If `'lt'` is treated as `'+'` and `'xx'` is treated as `'div'` then what us the value of `([(5lt15)]xx4)lt120` ?

Options

A. 25
B. 20
C. 5
D. 125

Answer

To solve the expression `([(5lt15)]xx4)lt120` where `'lt'` is treated as `'+'` and `'xx'` is treated as `'div'`, we can follow these steps:

### Step 1: Replace the symbols
First, we replace `'lt'` with `'+'` and `'xx'` with `'div'`. The expression becomes:
\[ [(5 + 15) \div 4] + 120 \]

### Step 2: Solve the expression inside the brackets
Now, we calculate the expression inside the brackets:
\[ 5 + 15 = 20 \]
So, we can rewrite the expression as:
\[ [20 \div 4] + 120 \]

### Step 3: Perform the division
Next, we perform the division:
\[ 20 \div 4 = 5 \]
Now, the expression simplifies to:
\[ 5 + 120 \]

### Step 4: Perform the addition
Finally, we add the two numbers:
\[ 5 + 120 = 125 \]

### Final Answer
Thus, the value of the expression `([(5lt15)]xx4)lt120` is:
\[ \boxed{125} \]