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A parallelogram PQRS ,the length of whos...

A parallelogram PQRS ,the length of whose sides are 8 cm and 12 cm ,has one diagonal 10 cm long .The length of the other diagonal is approximately :

A

17.8 cm

B

17.5 cm

C

17 cm

D

18 cm

Text Solution

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The correct Answer is:
To find the length of the other diagonal in the parallelogram PQRS, we can use the formula relating the lengths of the diagonals and the sides of the parallelogram: \[ d_1^2 + d_2^2 = 2(l^2 + b^2) \] Where: - \( d_1 \) and \( d_2 \) are the lengths of the diagonals, - \( l \) is the length of one side, - \( b \) is the length of the other side. Given: - \( l = 12 \, \text{cm} \) - \( b = 8 \, \text{cm} \) - \( d_1 = 10 \, \text{cm} \) We need to find \( d_2 \). ### Step 1: Calculate \( l^2 \) and \( b^2 \) First, we calculate \( l^2 \) and \( b^2 \): \[ l^2 = 12^2 = 144 \] \[ b^2 = 8^2 = 64 \] ### Step 2: Calculate \( 2(l^2 + b^2) \) Now, we calculate \( 2(l^2 + b^2) \): \[ l^2 + b^2 = 144 + 64 = 208 \] \[ 2(l^2 + b^2) = 2 \times 208 = 416 \] ### Step 3: Substitute values into the diagonal formula Now we substitute \( d_1 \) and the calculated value into the formula: \[ d_1^2 + d_2^2 = 416 \] Substituting \( d_1 = 10 \): \[ 10^2 + d_2^2 = 416 \] \[ 100 + d_2^2 = 416 \] ### Step 4: Solve for \( d_2^2 \) Now, we solve for \( d_2^2 \): \[ d_2^2 = 416 - 100 \] \[ d_2^2 = 316 \] ### Step 5: Calculate \( d_2 \) Now, we take the square root to find \( d_2 \): \[ d_2 = \sqrt{316} \] To approximate \( \sqrt{316} \): \[ \sqrt{316} \approx 17.78 \, \text{cm} \] Thus, the length of the other diagonal \( d_2 \) is approximately \( 17.78 \, \text{cm} \). ### Final Answer The length of the other diagonal is approximately \( 17.8 \, \text{cm} \). ---
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