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In quadratic equation cx^(2) + bx + c = ...

In quadratic equation `cx^(2) + bx + c = 0` find the ratio `b : c` if the given equation has equal roots

A

`1 : 2`

B

`2 : 1`

C

`4 : 1`

D

`1 : 4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio \( b : c \) in the quadratic equation \( cx^2 + bx + c = 0 \) when it has equal roots, we can follow these steps: ### Step 1: Identify the standard form of the quadratic equation The given quadratic equation is: \[ cx^2 + bx + c = 0 \] Here, \( a = c \), \( b = b \), and \( c = c \). ### Step 2: Use the condition for equal roots For a quadratic equation to have equal roots, the discriminant must be zero. The discriminant \( D \) is given by: \[ D = b^2 - 4ac \] Setting the discriminant equal to zero for equal roots: \[ b^2 - 4ac = 0 \] ### Step 3: Substitute the values of \( a \), \( b \), and \( c \) Substituting \( a = c \) into the discriminant equation: \[ b^2 - 4(c)(c) = 0 \] This simplifies to: \[ b^2 - 4c^2 = 0 \] ### Step 4: Rearranging the equation Rearranging gives: \[ b^2 = 4c^2 \] ### Step 5: Taking the square root Taking the square root of both sides: \[ b = 2c \quad \text{or} \quad b = -2c \] ### Step 6: Finding the ratio Now, we can express the ratio \( b : c \): \[ \frac{b}{c} = 2 \quad \text{or} \quad \frac{b}{c} = -2 \] Thus, the ratio \( b : c \) can be written as: \[ b : c = 2 : 1 \quad \text{or} \quad b : c = -2 : 1 \] ### Conclusion The ratio \( b : c \) when the quadratic equation has equal roots is \( 2 : 1 \) (considering positive roots). ---
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