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S can finish 50% of a work in a day . T ...

S can finish 50% of a work in a day . T can do 25% of the work in day. Both of them together will finish the work in____days.
A. 1
B. 2
C. 1.33
D. 3

A

A

B

C

C

D

D

B

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine how many days S and T will take to finish the work together based on their individual work rates. ### Step-by-Step Solution: 1. **Determine Individual Work Rates:** - S can finish 50% of the work in 1 day. Therefore, in terms of the whole work: \[ \text{Work done by S in 1 day} = 0.5 \text{ (or } \frac{1}{2} \text{ of the work)} \] This means S can complete the entire work in: \[ \text{Total days for S} = \frac{1}{0.5} = 2 \text{ days} \] - T can finish 25% of the work in 1 day. Therefore, in terms of the whole work: \[ \text{Work done by T in 1 day} = 0.25 \text{ (or } \frac{1}{4} \text{ of the work)} \] This means T can complete the entire work in: \[ \text{Total days for T} = \frac{1}{0.25} = 4 \text{ days} \] 2. **Calculate Individual Efficiencies:** - The efficiency of S (work done per day) is: \[ \text{Efficiency of S} = \frac{1}{2} \text{ (work/day)} \] - The efficiency of T (work done per day) is: \[ \text{Efficiency of T} = \frac{1}{4} \text{ (work/day)} \] 3. **Combine Efficiencies:** - The combined efficiency of S and T when working together is: \[ \text{Combined Efficiency} = \text{Efficiency of S} + \text{Efficiency of T} = \frac{1}{2} + \frac{1}{4} \] - To add these fractions, find a common denominator (which is 4): \[ \frac{1}{2} = \frac{2}{4} \] Thus, \[ \text{Combined Efficiency} = \frac{2}{4} + \frac{1}{4} = \frac{3}{4} \text{ (work/day)} \] 4. **Calculate Total Days to Complete the Work:** - The total work is considered as 1 (whole work). - The total days required to complete the work together is given by: \[ \text{Total Days} = \frac{\text{Total Work}}{\text{Combined Efficiency}} = \frac{1}{\frac{3}{4}} = \frac{4}{3} \text{ days} \] - Converting \(\frac{4}{3}\) days to a decimal gives approximately: \[ 1.33 \text{ days} \] ### Final Answer: Both S and T together will finish the work in approximately **1.33 days**.
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