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The mean of a distribution is 11 and the...

The mean of a distribution is 11 and the standard deviation in 5 . What is the value of the coefficient variation ?

A. `45.45%`

B. `35.35%`

C. `25.25%`

D. `55.55%`

A

A

B

B

C

D

D

C

Text Solution

AI Generated Solution

The correct Answer is:
To find the coefficient of variation (CV), we use the formula: \[ \text{Coefficient of Variation (CV)} = \left( \frac{\text{Standard Deviation}}{\text{Mean}} \right) \times 100 \] ### Step-by-Step Solution: 1. **Identify the given values**: - Mean (μ) = 11 - Standard Deviation (σ) = 5 2. **Substitute the values into the formula**: \[ CV = \left( \frac{5}{11} \right) \times 100 \] 3. **Calculate the fraction**: \[ \frac{5}{11} \approx 0.4545 \] 4. **Multiply by 100 to get the percentage**: \[ CV \approx 0.4545 \times 100 = 45.45\% \] 5. **Final Result**: The coefficient of variation is approximately **45.45%**. ### Conclusion: The correct answer is **A. 45.45%**.
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