Home
Class 14
MATHS
Monal Kumar travelled equal distance wit...

Monal Kumar travelled equal distance with speed of 3 km/hr, 5 km/hr and 8 km/hr and takes a total time of 39.5 minutes. Find the total distance in km.
A. 4
B. 2
C. 1
D. 3

A

D

B

A

C

C

D

D

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the total distance Monal Kumar traveled given that he traveled equal distances at different speeds and took a total time of 39.5 minutes. ### Step 1: Define the distance Let the distance traveled at each speed be \( x \) km. ### Step 2: Calculate the time taken for each speed - Time taken at 3 km/hr: \[ t_1 = \frac{x}{3} \text{ hours} \] - Time taken at 5 km/hr: \[ t_2 = \frac{x}{5} \text{ hours} \] - Time taken at 8 km/hr: \[ t_3 = \frac{x}{8} \text{ hours} \] ### Step 3: Total time in hours The total time taken is given as 39.5 minutes. We need to convert this into hours: \[ 39.5 \text{ minutes} = \frac{39.5}{60} \text{ hours} \] ### Step 4: Set up the equation for total time The total time can be expressed as: \[ t_1 + t_2 + t_3 = \frac{39.5}{60} \] Substituting the expressions for \( t_1, t_2, \) and \( t_3 \): \[ \frac{x}{3} + \frac{x}{5} + \frac{x}{8} = \frac{39.5}{60} \] ### Step 5: Find a common denominator The least common multiple (LCM) of 3, 5, and 8 is 120. We can rewrite the left side: \[ \frac{40x}{120} + \frac{24x}{120} + \frac{15x}{120} = \frac{39.5}{60} \] Combining the fractions: \[ \frac{(40 + 24 + 15)x}{120} = \frac{39.5}{60} \] This simplifies to: \[ \frac{79x}{120} = \frac{39.5}{60} \] ### Step 6: Cross-multiply to solve for \( x \) Cross-multiplying gives: \[ 79x \times 60 = 39.5 \times 120 \] Calculating the right side: \[ 39.5 \times 120 = 4740 \] So we have: \[ 4740 = 79x \times 60 \] ### Step 7: Isolate \( x \) Now, divide both sides by 79: \[ x = \frac{4740}{79 \times 60} \] Calculating \( 79 \times 60 = 4740 \): \[ x = \frac{4740}{4740} = 1 \] ### Step 8: Calculate total distance Since Monal traveled the same distance \( x \) at three different speeds, the total distance traveled is: \[ \text{Total Distance} = 3x = 3 \times 1 = 3 \text{ km} \] ### Final Answer The total distance Monal Kumar traveled is **3 km**. Thus, the correct option is **D. 3**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

Chandan travelled equal distance with speed of 3 km/hr, 4 km/hr and 8 km/hr and takes a total time of 42.5 minutes. Find the total distance in km. A. 4 B. 2 C. 1 D. 3

A person travels equal distances with speeds of 3km/hr, 4 km/hr and 5km/hr and takes a total time of 47 minutes. The total distance (in km) is:

A person travels equal distances with speeds of 3 km/hr, 4 km/hr and 5 km/hr and takes a to a time of 47 minutes. The total distance (in km) is 2 b. 3 c. 4 d. 5

Apurva travelled equal distances at speeds of 10 km.hr, 20 km.h and 6km/hr and took a total time of 19 minutes . Find the total distance travelled in km

A person travels equal distances with speeds of 4 km/h, 6 km/h and 8 km/h. He takes a total time of 32.5 minutes. Find the total distance travelled by him

Mr. Prasad travelled equal distances at spoods of 2 km/hr , 4 km/hr., and 6 km/hr., and took a total of 55 minutes to complete. Find the total distance he travelled, in km.