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Two numbers are in ratio 3 : 4. When 3 i...

Two numbers are in ratio 3 : 4. When 3 is subtracted from both the mumbers, the ratio becomes 2 : 3. Find the sum of the numbers.
A. 16
B. 20
C. 21
D. 22

A

C

B

B

C

D

D

A

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the information given in the question. ### Step 1: Define the numbers Let the two numbers be \( x \) and \( y \). According to the problem, the ratio of the two numbers is given as: \[ \frac{x}{y} = \frac{3}{4} \] This implies that: \[ x = \frac{3}{4}y \] ### Step 2: Set up the equation after subtraction When 3 is subtracted from both numbers, the new ratio becomes: \[ \frac{x - 3}{y - 3} = \frac{2}{3} \] Cross-multiplying gives us: \[ 3(x - 3) = 2(y - 3) \] ### Step 3: Substitute \( x \) in the equation Substituting \( x = \frac{3}{4}y \) into the equation: \[ 3\left(\frac{3}{4}y - 3\right) = 2(y - 3) \] Expanding both sides: \[ \frac{9}{4}y - 9 = 2y - 6 \] ### Step 4: Eliminate the fraction To eliminate the fraction, multiply the entire equation by 4: \[ 9y - 36 = 8y - 24 \] ### Step 5: Solve for \( y \) Rearranging the equation gives: \[ 9y - 8y = 36 - 24 \] \[ y = 12 \] ### Step 6: Find \( x \) Now that we have \( y \), we can find \( x \): \[ x = \frac{3}{4}y = \frac{3}{4} \times 12 = 9 \] ### Step 7: Calculate the sum of the numbers Now, we can find the sum of the two numbers: \[ x + y = 9 + 12 = 21 \] ### Final Answer The sum of the numbers is: \[ \boxed{21} \]
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