यदि x = a ( theta - sin theta ) , y = a ...

यदि `x = a ( theta - sin theta ) , y = a ( 1 - cos theta ),` तब ` (d ^(2) y )/(dx ^(2))` होगा

A

`- (1)/( a sin ^(2) theta //2)`

B

`- (1)/( 4a) cosec ^(2) "" (theta)/(2)`

C

`- (1)/(4a) sec ^(2) "" (theta )/(2) cosec^(2) "" (theta)/(2)`

D

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The correct Answer is:

D

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