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(""^8C0)/6-""^8C1+""^8C2 .6-""^8C3 .6^2+...

`(""^8C_0)/6-""^8C_1+""^8C_2 .6-""^8C_3 .6^2+....+ ""^8C_8 .6^7` =

A

0

B

`6^7`

C

`6^8`

D

`5^8/6`.

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MODERN PUBLICATION-BINOMIAL THEOREM-EXERCISE
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