Let `S_(n)` denote the sum of n terms of an AP, if `S_(2n)=3S_(n)`, then the ratio `(S_(3n))/(S_(n))` is equal to

Let S_n denote the sum of first n terms of an AP and 3S_n=S_(2n) What is S_(3n):S_n equal to? What is S_(3n):S_(2n) equal to?

The sum of n terms of an A.P. is 3n^2 + 4n . Find the A.P.

If the sum of n terms of an A.P. is 3n^2 + 2n : Find the rth term.

If S_(1),S_(2),S_(3) be respectively the sum of n, 2n and 3n terms of a GP, then (S_(1)(S_(3)-S_(2)))/((S_(2)-S_(1))^(2)) is equal to

Find the sum of first n terms of an A.P. whose nth term is 3n+1.

If the sum of n terms of an A.P. is given by delta_n=3n+2n^2 , then the common difference of an A.P. is

The ratio of the sums of m and n terms of an A.P. is m^2: n^2 . Show that the ratio of m^(th) and n^(th) term is (2m - 1 ) : (2n -1).

Let the sum of n, 2n, 3n terms of an A.P. be S_1 , S_2 and S_3 , respectively, show that S_3 = 3(S_2 - S_1)

In an A.P., S_(3)=6 and S_(6)=3 prove that: 2(2n+1)S_(n+4)=(n+4)S_(2n+1) .

Consider an AP with a as the first term and d is the common difference such that S_(n) denotes the sum to n terms and a_(n) denotes the nth term of the AP. Given that for some m, n inN,(S_(m))/(S_(n))=(m^(2))/(n^(2))(nen) . Statement 1 d=2a because Statement 2 (a_(m))/(a_(n))=(2m+1)/(2n+1) .