The line 2x-3y=4 is perpendicular bisector of the line AB. If the coordinates of A are (-3,1). Fiind the coordinates of B.

Find the equation of the plane passing through the point (3,-3, 1) and perpendicular to the line joining the points (3, 4, - 1) and (2, - 1,5). Also find the coordinates of the foot of the perpendicular, the equation of the perpendicular line and the length of perpendicular drawn from the origin to the plane.

To draw the perpendicular bisector of line segment AB, we open the compass

Let P be a point on the circle x^(2)+y^(2)=9 , Q a point on the line 7x+y+3=0 , and the perpendicular bisector of PQ be the line x-y+1=0 . Then the coordinates of P are

In a triangle, ABC, the equation of the perpendicular bisector of AC is 3x - 2y + 8 = 0 . If the coordinates of the points A and B are (1, -1) & (3, 1) respectively, then the equation of the line BC will be

Write the coordinates of the image of the point (3,8) in the lines x+3y-7=0.

The line of greatest slope on an inclined plane P_1 is the line in the plane P_1 which is perpendicular to the line of intersection of the plane P_1 and a horizontal plane P_2 . Q. The coordinate of a point on the plane 2x+y-5z=0, 2sqrt(11) unit away from the line of intersection of 2x+y-5z=0 and 4x-3y+7z=0 are

Let ABC be a triangle and A -= (1,2) ,y = x be the perpendicular bisector of AB and x-2y+1=0 be the perpendicular bisector of angle C . If the equation of BC is given by ax+by-5 = 0 then the value of a -2b is

Find the equation of a line passing through the points A(0, 6, -9) and B(-3,-6,3). If D is the foot of the perpendicular drawn from a point C(7,4,-1) on the line AB, then find the coordinates of the point D and the equation of line CD.

Find the equations of the perpendicular from the point (3, -1, 11) to the line (x)/(2)=(y-2)/(3)=(z-3)/(4) . Also find the coordinates of the foot of the perpendicular and length of the perpendicular.