Home
Class 12
CHEMISTRY
Iron has an edge length 288 pm. Its dens...

Iron has an edge length 288 pm. Its density is `7.86 gm//cm^(3)` . Find the type of cubic lattice to which crystal belongs. (At. mass of iron = 56)

Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER 2022

    ICSE MODEL PAPER|Exercise PART II (SECTION B)|11 Videos
  • SAMPLE PAPER 2022

    ICSE MODEL PAPER|Exercise PART II (SECTION C)|15 Videos
  • SAMPLE PAPER 2022

    ICSE MODEL PAPER|Exercise PART II (SECTION C)|15 Videos

Similar Questions

Explore conceptually related problems

The density of iron is 7.869 g//cm^(3) . Express it in SI units.

Iron has body centred cubic cell with a cell edge of 286.5 pm. The density of iron is 7.87 g cm^(-3) . Use this information to calculate Avogadro's number. (Atomic mass of Fe = 56 mol^(-3) )

Iron has body centred cubic cell with a cell edge of 286.5 pm. The density of iron is 7.87 g cm^(-3) . Use this information to calculate Avogadro's number. (Atomic mass of Fe = 56 mol^(-3) )

Iron has body centred cubic cell with a cell edge of 286.5 pm. The density of iron is 7.87 g cm^(-3) . Use this information to calculate Avogadro's number. (Atomic mass of Fe = 56 mol^(-3) )

Iron has body centred cubic cell with a cell edge of 286.5 pm. The density of iron is 7.87 g cm^(-3) . Use this information to calculate Avogadro's number. (Atomic mass of Fe = 56 mol^(-3) )

Iron has body centred cubic cell with a cell edge of 286.5 pm. The density of iron is 7.87 g cm^(-3) . Use this information to calculate Avogadro's number. (Atomic mass of Fe = 56 mol^(-3) )

The mass of an iron ball is 312 g. The density of iron is 7.8 g cm^(-3) . Find the volume of the ball.

Using the data given below, find the type of cubic lattice to which the crystal belongs. {:(,Fe,V,Pd),("a in pm",286,301,388),(rho" in gm cm"^(-3),7.86,5.96,12.16):}

An element crystallising in body centred cublic lattice has edge length of 500 pm. If the density is 4 g cm^(-3) , the atomic mass of the element ("in g mol"^(-1)) is (consider N_(A)=6xx10^(23))

An element crystallising in body centred cublic lattice has edge length of 500 pm. If the density is 4 g cm^(-3) , the atomic mass of the element ("in g mol"^(-1)) is (consider N_(A)=6xx10^(23))