Calculate the amount of heat given out while 400 g of water at `30^@C` is
cooled and converted into ice at `-2^@C`.
Specific heat capacity of water = 4200 J/kg K
Specific heat capacity of ice = 2100 J/ kg K
Specific latent heat of fusion of ice = 33600 J/kg

Calculate the total amount of heat energy required to convert 100 g of ice at -10^@ C completely into water at 100^@ C. Specific heat capacity of ice = 2.1 J g^(-1) K^(-1) , specific heat capacity of water = 4.2 J g^(-1) K^(-1) , specific latent heat of ice = 336 J g^(-1)

A calorimeter of mass 60 g contains 180 g of water at 29^(@)C . Find the final temperature of the mixture, when 37.2 g of ice at - 10^(@)C is added to it (specific heat capacity of water = 4200 J//kg K. latent heat of ice 336 xx 10^(3)J//kg . Specific heat capacity of ice = 2100 J//kg K , specific heat capacity of the calorimeter is 0.42 Jg^(-1) xx C^(-1) )

How much heat energy is released when 5.0 g of water at 20^@ C changes into ice at 0^@ C ? Take specific heat capacity of water = 4.2 J g^(-1) K^(-1) , specific latent heat of fusion of ice = 336 J g^(-1) .

A piece of ice of mass 40 g is added to 200 g of water at 50^@ C. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water = 4200 J kg^(-1) K^(-1) and specific latent heat of fusion of ice = 336 xx 10^3" J "kg^(-1) .

How much heat energy is released when 5 g of water at 20^(@)C changes to ice at 0^(@)C ? [Specific heat capacity of water = 4.2Jg^(-1)""^(@)C^(-1) Specific latent heat of fusion of ice = 336Jg^(-1) ]

Calculate the amount of heat energy required to raise the temperature of 100 g of copper from 20^@ C to 70^@ C. Specific heat capacity of copper = 390 J kg^(-1) K^(-1)

The temperature of 170 g of water at 50^@ C is lowered to 5^@ C by adding certain amount of ice to it. Find the mass of ice added. Given : Specific heat capacity of water = 4200 J kg^(-1)^@C^(-1) and specific latent heat of ice = 336000 J kg^(-1) .

In an insulated vessel, 250 g of ice at 0^(@)C is added to 600 g of water at 18^(@)C (a) What is the final temperature of the system? (b) How much ice remains when the system reaches equilibrium? Useful data: Specific heat capacity of water: 4190 K/K.kg Speicific heat capacity of ice: 2100J/K.kg Latent heat of fusio of ice: 3.34xx10^(5)J//kg

State in brief, the meaning of each of the following: The specific latent heat of fusion of ice is 336000 J kg^(-1)

Find the quantity of heat required to convert 40 g of ice at -20^(@) C into water at 20^(@) C. Given L_(ice) = 0.336 xx 10^(6) J/kg. Specific heat of ice = 2100 J/kg-K Specific heat of water = 4200 J/kg-K