Current 'I' flowing through a metallic wire of area of cross-section 'a' is given by the equation `I = "naev"_(d)`. What is the meaning of the symbols 'n' and '`v_(d)`'?

A stready current i is flowing through a conductor of uniform cross-section. Any segment of the conductor has

Current is flowing through a wire of non-uniform cross section. Cross section of wire at A is les than the cross section of wire at B. Then match the following

Assertion : Current I is flowing through a cylindrical wire of non-uniform cross-section as shown. Section of wire near A will be more heated compared to the section near B. Reason : Current density near A is more.

A current is flowing through a conducting hollow pipe whose area of cross-section is shown in the fig. The value of magnetic induction will be zero at-

A current i passes through a wire of length l , radius of cross-section r and resistivity rho . The rate of heat generation is

When a steady current flows through a metal conductor of non-uniform cross-section , then drift velocity is

A current .I. flows through a metallic wire of radius .r. and the free electrons in it drift with a velocity v_(d) . Calculate the drift velocity of the free electrons through the wire of the same material, having double the radius, when same current flows through it.

The current I_(1) (in A) flowing through the 1Omega resistor in the given circuit is

A steady current is set up in a metalic wire of non- uniform cross-section. How is the rate of flow free electrons related

Assertion : If a current is flowing through a conducting wire of non-uniform cross-section, drift speed and resistance both will increase at a section where cross-sectional area is less. Reason : Current density at such sections is more where cross-sectional area is less.