What is meant by resolving power of a telescope ?

Diameter of the objective of a telescope is 200cm. What is the resolving power of a telescope? Take wavelength of light =5000Å.

Assume that light of wavelength 500 nm is used to illuminate a telescope. What is the resolving power of a telescope whose objective has a radius of 200 cm ?

Resolving power of a telescope increases with

A small telescope has an objective lens of focal length 144 cm and an eye-piece of focal length 6.0 cm . What is the magnifying power of the telescope ? What is the separation between the objective and the eye-piece ?

A small telescope has an objective lens of focal length 144 cm and an eye-piece of focal length 6.0 cm . What is the magnifying power of the telescope ? What is the separation between the objective and the eye-piece ?

Assertion (A) To increase resolving power of a telescope, the aperture (a) of the object should be large. Reason (R ) Resolving power of the telescope is given by (2a)/(1.22lambda) .

A: The resolving power of a telescope decreases on decreasing the aperture of its objective lens. R: The resolving power of a telescope is given as D/(1.22 lamda) where D is aperture of the objective and lamda is the wavelength of light.

Define magnifying power and resolving power of a telescope.

Calculate the least value of the angular separation of two stars which can be resolved by a telescope of 200 cm aperture. If the aperture of the human eye be 2mm and if the focal length of the eyepiece be 1 inch, what must be the minimum focal length of the objective if full resolving power of the telescope is to be utilized. Take lambda = 5500 A^(0) .

What is meant by dispersive power of a transparent material ?