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What well Centre in place of the questio...

What well Centre in place of the question mark (?) in the following questions?
`(8)/(21)` of 189 = `(?)^2 -: 2`

A

6

B

36

C

`sqrt(6)`

D

12

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AI Generated Solution

The correct Answer is:
To solve the equation \( \frac{8}{21} \times 189 = \frac{(?)^2}{2} \), we will follow these steps: ### Step 1: Calculate \( \frac{8}{21} \times 189 \) To find the left side of the equation, we first need to calculate \( \frac{8}{21} \) of 189. \[ \frac{8}{21} \times 189 = \frac{8 \times 189}{21} \] ### Step 2: Simplify \( \frac{189}{21} \) Now, we simplify \( \frac{189}{21} \): \[ 189 \div 21 = 9 \] So, we can rewrite the equation as: \[ \frac{8 \times 189}{21} = 8 \times 9 = 72 \] ### Step 3: Set up the equation Now we have: \[ 72 = \frac{(?)^2}{2} \] ### Step 4: Multiply both sides by 2 To isolate \( (?)^2 \), we multiply both sides of the equation by 2: \[ 72 \times 2 = (?)^2 \] \[ 144 = (?)^2 \] ### Step 5: Solve for \( ? \) Now, we take the square root of both sides to find the value of \( ? \): \[ ? = \sqrt{144} \] \[ ? = 12 \quad \text{or} \quad ? = -12 \] ### Final Answer Thus, the value that will replace the question mark is \( \pm 12 \). ---
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UPKAR PUBLICATION -PRACTICE SET-3-PART-III QUANTIATIVE APTITUTE
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